💡
Seb's Whiteboard
  • 👨‍💻Welcome, I'm Sebastien St Vil
  • Extras
    • Gradient Descent
    • How I learned Java
    • Machine Learning by Andrew Ng
  • Projects
    • 📉Backtest Equity Trading with SMA Strategy
    • Wellington GA Lab
    • Stock analysis
    • 📈Time Series Regression-based Trading Strategy
  • Arrays & Strings
    • Best Time to Buy and Sell Stock II
    • Online Stock Span
    • Implement strStr()
    • 2Sum
    • 3Sum
    • 3Sum Closest
    • 4Sum II
    • Set Matrix Zeroes
    • Group Anagrams
    • Longest Substring Without Repeating Characters
    • Remove Duplicates from Sorted Array
    • Move Zeroes
    • Valid Sudoku
    • Rotate Image
    • First Unique Character in a String
    • Design a Circular Queue
    • Longest Common Prefix
  • Binary Tree
  • Second Minimum Node In a Binary Tree (671)
  • Design
  • LRU Cache
  • Min Stack (155)
  • Sorting & Searching
    • Merge Sorted Array (88)
    • First Bad Version
  • Math
    • Power of Three (326)
    • Power of Two (231)
    • Count Prime (204)
    • Roman to Integer (13)
    • Fizz Buzz (412)
    • Count-and-Say
  • Dynamic Programming
    • Pascal's Triangle (118)
  • Linked List
    • Copy List with Random Pointer
    • Remove Nth Node From End of List
    • Remove Duplicated from Sorted List II
  • Tips
    • Finding dups
  • Sliding Window
    • Subarray Product Less Than K
Powered by GitBook
On this page

Was this helpful?

  1. Sorting & Searching

First Bad Version

You are a product manager and currently leading a team to develop a new product. Unfortunately, the latest version of your product fails the quality check. Since each version is developed based on the previous version, all the versions after a bad version are also bad.

Suppose you have n versions [1, 2, ..., n] and you want to find out the first bad one, which causes all the following ones to be bad.

You are given an API bool isBadVersion(version) which returns whether version is bad. Implement a function to find the first bad version. You should minimize the number of calls to the API.

Solution:

You could start from the beginning and do a linear search thorugh your product versions one by one until you land on the bad one however if consider that you have a 2500 product versions, if it takes one minute to search and test one version, it would therefore take you almost 2 days to arrive to answer in the worst-case scenario that the first bad version is at n-2 position. Time Complexity : O(N)

We can do better with the Binary Search Algorithm

/* The isBadVersion API is defined in the parent class VersionControl.
      boolean isBadVersion(int version); */

public class Solution extends VersionControl {
    public int firstBadVersion(int n) {
        int start = 1, end = n;
        
        while(start <= end){
            int mid = end + (start - end) / 2;
            if(isBadVersion(mid)){
                end = mid - 1;
            }
            else{
                start = mid + 1;
            }
        }
        return start;
    }
}

Time Complexity: O(logN)

PreviousMerge Sorted Array (88)NextPower of Three (326)

Last updated 4 years ago

Was this helpful?